The electric field $(E)$ and magnetic field $(B)$ of an electromagnetic wave passing through vacuum are given by
$E = E_0 \sin (kx - \omega t)$
$B = B_0 \sin (kx - \omega t)$
Then the correct statement among the following is

If the magnetic field in a plane electromagnetic wave is given by $\overrightarrow{B} = 3 \times 10^{-8} \sin (1.6 \times 10^{3} x + 48 \times 10^{10} t) \hat{j} \; T$,then what will be the expression for the electric field?

$A$ plane electromagnetic wave of frequency $500\, MHz$ is travelling in vacuum along $y$-direction. At a particular point in space and time,$\overrightarrow{B} = 8.0 \times 10^{-8} \hat{z}\, T$. The value of electric field at this point is (speed of light $c = 3 \times 10^{8}\, m/s$). $\hat{x}, \hat{y}, \hat{z}$ are unit vectors along $x, y$ and $z$ directions.

The magnetic field of an $\text{E.M.}$ wave is given by $\overrightarrow{ B }=\left(\frac{\sqrt{3}}{2} \hat{ i }+\frac{1}{2} \hat{ j }\right) 30 \sin \left[\omega\left( t -\frac{ z }{ c }\right)\right]$ ($\text{S.I.}$ units). The corresponding electric field in $\text{S.I.}$ units is:

An electromagnetic wave of intensity $50 \ W m^{-2}$ enters a medium of refractive index $n$ without any loss. The ratio of the magnitudes of electric fields and the ratio of the magnitudes of magnetic fields of the wave before and after entering the medium are respectively given by:

What do electromagnetic waves $NOT$ transport?