The electric field between the plates of a parallel plate capacitor is $E$. If the charge on the plates is $Q$, then the force on each plate is:

  • A
    $\frac{QE^2}{2}$
  • B
    $QE$
  • C
    $\frac{QE}{2}$
  • D
    $\frac{Q^2}{2\epsilon_0 A}$

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