The unit of absolute permittivity is

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The formula for the capacitance of a parallel plate capacitor is $C = \frac{\epsilon A}{d}$,where $\epsilon$ is the absolute permittivity,$A$ is t

Vedclass · Accepted Answer

$F \cdot m^{-1}$

Vedclass · Answer

(B) The formula for the capacitance of a parallel plate capacitor is $C = \frac{\epsilon A}{d}$,where $\epsilon$ is the absolute permittivity,$A$ is the area,and $d$ is the distance between plates.Rearranging for $\epsilon$,we get $\epsilon = \frac{C \cdot d}{A}$.The unit of capacitance $C$ is Farad $(F)$,the unit of distance $d$ is meter $(m)$,and the unit of area $A$ is square meter $(m^2)$.Substituting these units: $	ext{Unit of } \epsilon = \frac{F \cdot m}{m^2} = F \cdot m^{-1}$.Therefore,the unit of absolute permittivity is $F \cdot m^{-1}$.

Similar Questions

The capacity of a parallel plate capacitor depends on:

$A$ parallel plate capacitor is formed by connecting $n$ plates placed at equal distances alternately. If the capacitance between any two adjacent plates is $C$,find the resultant capacitance.

$A$ parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge,potential,and capacitance respectively are:

Two parallel plates separated by $d \ mm$ are kept at a potential difference of $V \ V$. $A$ particle of mass $m$ and charge $q$ enters the region between them with some velocity. The acceleration of the particle will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module