The electrical force between two point charge | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the two point charges be $q_1$ and $q_2$,separated by a distance $r$. The initial force is given by Coulomb's Law: $F = \frac{k q_1 q_2}{r^2}

Vedclass · Accepted Answer

$198$

Vedclass · Answer

(C) Let the two point charges be $q_1$ and $q_2$,separated by a distance $r$. The initial force is given by Coulomb's Law: $F = \frac{k q_1 q_2}{r^2} = 200 \ N$.When the charge $q_1$ increases by $10 \ \%$,the new charge is $q_1' = q_1 + 0.1 q_1 = 1.1 q_1$.When the charge $q_2$ decreases by $10 \ \%$,the new charge is $q_2' = q_2 - 0.1 q_2 = 0.9 q_2$.The new electrical force $F'$ at the same distance $r$ is: $F' = \frac{k q_1' q_2'}{r^2} = \frac{k (1.1 q_1) (0.9 q_2)}{r^2}$.Substituting the initial force value: $F' = (1.1 	imes 0.9) 	imes \frac{k q_1 q_2}{r^2} = 0.99 	imes F$.Therefore,$F' = 0.99 	imes 200 \ N = 198 \ N$.

The electrical force between two point charges is $200 \ N$. If we increase $10 \ \%$ charge on one of the charges and decrease $10 \ \%$ charge on the other,then the electrical force between them for the same distance becomes . . . . . . . . . . (in $N$)

Similar Questions

Two positive ions,each carrying a charge $q,$ are separated by a distance $d.$ If $F$ is the force of repulsion between the ions,the number of electrons missing from each ion will be ($e$ being the charge on an electron).

$A$ $10\,\mu C$ charge is divided into two parts and placed at $1\,cm$ distance so that the repulsive force between them is maximum. The charges of the two parts are :

Explain the superposition principle for static electric forces and write its general equation.

Two equal charges are separated by a distance $d$. $A$ third charge placed on a perpendicular bisector at $x$ distance will experience maximum Coulomb force when

The value of the electric permittivity of free space $(\varepsilon_0)$ is ........

Vedclass Test Series

Exam Paper Generator

Online Exam Module