The electronic configuration of a metal ion in its complex is $[Ar] 3d^4$. For this metal complex,$\Delta_o < P$ ($P=$ energy required for electron pairing in a single orbital). The distribution of electrons in the complex is:
- A$(t_{2g})^3 (e_g)^1$
- B$(t_{2g})^2 (e_g)^2$
- C$(t_{2g})^4 (e_g)^0$
- D$(t_{2g})^1 (e_g)^3$
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Match List-$I$ with List-$II$.
List-$I$ (Coordination entity) List-$II$ (Wavelength of light absorbed in $nm$) $A$. $[CoCl(NH_3)_5]^{2+}$ $I$. $310$ $B$. $[Co(NH_3)_6]^{3+}$ $II$. $475$ $C$. $[Co(CN)_6]^{3-}$ $III$. $535$ $D$. $[Cu(H_2O)_4]^{2+}$ $IV$. $600$
Choose the correct answer from the options given below:
| List-$I$ (Coordination entity) | List-$II$ (Wavelength of light absorbed in $nm$) |
|---|---|
| $A$. $[CoCl(NH_3)_5]^{2+}$ | $I$. $310$ |
| $B$. $[Co(NH_3)_6]^{3+}$ | $II$. $475$ |
| $C$. $[Co(CN)_6]^{3-}$ | $III$. $535$ |
| $D$. $[Cu(H_2O)_4]^{2+}$ | $IV$. $600$ |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2023
View SolutionFor an octahedral complex,which of the following $d-$electronic configuration will give the maximum magnitude of crystal field stabilization energy,in terms of $\Delta_{o}$?
Match the following complexes in List-$I$ with their electronic configurations in List-$II$.
List-$I$ (Complex) List-$II$ (Electronic configuration of metal/ion) $A. [Co(NH_3)_6]^{3+}$ $I. t_{2g}^5 e_g^0$ $B. [CoF_6]^{3-}$ $II. t_{2g}^6 e_g^0$ $C. [Ni(CO)_4]$ $III. t_{2g}^4 e_g^2$ $D. [Fe(CN)_6]^{3-}$ $IV. t^4 e^6$
| List-$I$ (Complex) | List-$II$ (Electronic configuration of metal/ion) |
|---|---|
| $A. [Co(NH_3)_6]^{3+}$ | $I. t_{2g}^5 e_g^0$ |
| $B. [CoF_6]^{3-}$ | $II. t_{2g}^6 e_g^0$ |
| $C. [Ni(CO)_4]$ | $III. t_{2g}^4 e_g^2$ |
| $D. [Fe(CN)_6]^{3-}$ | $IV. t^4 e^6$ |
The configurations of the complexes of manganese $A$ and $B$ respectively are $t_{2g}^3 e_g^1$ and $t_{2g}^4 e_g^0$. Then $A$ and $B$ are:
In the octahedral crystal field,the correct order of splitting for $I^{-}, H_2O, NH_3$ and $CN^{-}$ ligands is:
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