The electronic configuration of gadolinium (a | vedclass

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(B) The electronic configuration of $La$ $(Z=57)$ is $[Xe] 5d^1 6s^2$. Following this,the $4f$ orbitals are filled. Europium ($Eu$,$Z=63$) has a stabl

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$[Xe]4f^7 5d^1 6s^2$

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(B) The electronic configuration of $La$ $(Z=57)$ is $[Xe] 5d^1 6s^2$. Following this,the $4f$ orbitals are filled. Europium ($Eu$,$Z=63$) has a stable half-filled $4f$ subshell with the configuration $[Xe] 4f^7 6s^2$. For Gadolinium ($Gd$,$Z=64$),the next electron enters the $5d$ orbital instead of the $4f$ orbital to maintain the stability of the half-filled $4f^7$ configuration. Therefore,the electronic configuration of $Gd$ $(Z=64)$ is $[Xe] 4f^7 5d^1 6s^2$.

$E^{\Theta }$	$V$	$Cr$	$Mn$	$Fe$	$Co$	$Ni$	$Cu$
$(M^{2+}/M)$	$-1.18$	$-0.91$	$-1.18$	$-0.44$	$-0.28$	$-0.25$	$+0.35$

List-$I$	List-$II$
$(1) \ \text{Cr}$	$(A) \ [\text{Ar}] \ 3d^8 4s^0$
$(2) \ \text{Fe}^{2+}$	$(B) \ [\text{Ar}] \ 3d^{10} 4s^1$
$(3) \ \text{Ni}^{2+}$	$(C) \ [\text{Ar}] \ 3d^6 4s^0$
$(4) \ \text{Cu}$	$(D) \ [\text{Ar}] \ 3d^5 4s^1$
	$(E) \ [\text{Ar}] \ 3d^6 4s^2$

The electronic configuration of gadolinium (atomic no. $64$) is

Similar Questions

Which of the elements possess only one electron in the $5d$-orbital?

For the first row transition metals,the $E^{\Theta }$ values are:

$E^{\Theta }$ $V$ $Cr$ $Mn$ $Fe$ $Co$ $Ni$ $Cu$

$(M^{2+}/M)$ $-1.18$ $-0.91$ $-1.18$ $-0.44$ $-0.28$ $-0.25$ $+0.35$

Explain the irregularity in the above values.

Which of the following electronic configurations of a metal atom represents the highest oxidation state?

In the periodic table,the first transition series is placed in:

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