The emf of a battery is 2, V and its internal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The power delivered to an external circuit by a battery with emf $E$ and internal resistance $r$ is given by $P = I^2 R$,where $I = \frac{E}{R+r}$

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) The power delivered to an external circuit by a battery with emf $E$ and internal resistance $r$ is given by $P = I^2 R$,where $I = \frac{E}{R+r}$.Thus,$P = \left( \frac{E}{R+r} ight)^2 R$.For maximum power transfer,the external resistance $R$ must be equal to the internal resistance $r$ $(R = r)$.The formula for maximum power is $P_{	ext{max}} = \frac{E^2}{4r}$.Given $E = 2\, V$ and $r = 0.5\,\Omega$,we substitute these values:$P_{	ext{max}} = \frac{(2)^2}{4 	imes 0.5} = \frac{4}{2} = 2\, W$.

The emf of a battery is $2\, V$ and its internal resistance is $0.5 \,\Omega$. The maximum power which it can deliver to any external circuit will be ............. $watt$.

Similar Questions

$A$ constant voltage is applied between two ends of a metallic wire. If the length is halved and the radius of the wire is doubled,the rate of heat developed in the wire will be

If a power of $100\, W$ is being supplied across a potential difference of $200\, V$,the current flowing is ............ $A$.

$A$ wire of resistance $R$ is connected across a cell of emf $\varepsilon$ and internal resistance $r$. The current through the circuit is $I$. In time $t$,the work done by the battery to establish the current $I$ is

Heating coils rated at $220\, V$ are available with resistances of $55\,\Omega$,$110\,\Omega$,$220\,\Omega$,and $440\,\Omega$. Which resistance value will produce the maximum power?

$A$ $5\;A$ fuse wire can withstand a maximum power of $1\;W$ in the circuit. The resistance of the fuse wire is

Vedclass Test Series

Exam Paper Generator

Online Exam Module