The energy liberated on complete fission of 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The number of atoms in $1 \, kg$ of $_{92}U^{235}$ is given by $N = \frac{m}{M} 	imes N_A$,where $m = 1000 \, g$,$M = 235 \, g/mol$,and $N_A = 6.

Vedclass · Accepted Answer

$8.2 	imes 10^{13} \, J$

Vedclass · Answer

(C) The number of atoms in $1 \, kg$ of $_{92}U^{235}$ is given by $N = \frac{m}{M} 	imes N_A$,where $m = 1000 \, g$,$M = 235 \, g/mol$,and $N_A = 6.023 	imes 10^{23} \, atoms/mol$.$N = \frac{1000}{235} 	imes 6.023 	imes 10^{23} \approx 2.563 	imes 10^{24} \, nuclei$.Energy released per nucleus is $200 \, MeV = 200 	imes 1.602 	imes 10^{-13} \, J = 3.204 	imes 10^{-11} \, J$.Total energy liberated $E = N 	imes 200 \, MeV = 2.563 	imes 10^{24} 	imes 3.204 	imes 10^{-11} \, J$.$E \approx 8.21 	imes 10^{13} \, J \approx 8.2 	imes 10^{13} \, J$.

The energy liberated on complete fission of $1\, kg$ of $_{92}U^{235}$ is (Assume $200\, MeV$ energy is liberated on fission of $1$ nucleus).

Similar Questions

If $x$ is a solution of the equation $\sqrt{2x+1} - \sqrt{2x-1} = 1$ where $x \geq \frac{1}{2}$,then $\sqrt{4x^2-1}$ is equal to

For all integers $n \geq 1$, which of the following is divisible by $9$?

Determine the empirical formula of Kevlar,used in making bulletproof vests,if it contains $70.6 \% \, C, 4.2 \% \, H, 11.8 \% \, N$,and $13.4 \% \, O$.

In thermodynamics,which one of the following properties is not an intensive property?

Which of the following pairs of organs includes only the endocrine glands?

Vedclass Test Series

Exam Paper Generator

Online Exam Module