The energy released by the fission of one uranium nucleus is $200 \text{ MeV}$. The number of fissions per second required to produce $128 \text{ W}$ power is:

  • A
    $6 \times 10^{12}$
  • B
    $2 \times 10^{12}$
  • C
    $8 \times 10^{12}$
  • D
    $4 \times 10^{12}$

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Similar Questions

How much $MeV$ energy is emitted by the fission of one nucleus of uranium-$235$ (in $MeV$)?

The energy released when $\frac{7}{17.13} \text{ kg}$ of $^7_3\text{Li}$ is converted into $^4_2\text{He}$ by proton bombardment is $\alpha \times 10^{32} \text{ eV}$. The value of $\alpha$ is . . . . . . . (Nearest integer) (Mass of $^7_3\text{Li} = 7.0183 \text{ u}$, mass of $^4_2\text{He} = 4.004 \text{ u}$, mass of proton $= 1.008 \text{ u}$, $1 \text{ u} = 931 \text{ MeV/c}^2$, and Avogadro number $N_A = 6.0 \times 10^{23} \text{ mol}^{-1}$)

$A$ hydrogen bomb is based on which of the following phenomena?

An atomic power nuclear reactor can deliver $300\ MW$. The energy released due to fission of each nucleus of uranium atom $^{238}U$ is $170\ MeV$. The number of uranium atoms fissioned per hour will be:

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The disintegration energy $Q$ for the nuclear fission of ${ }^{235} U \rightarrow{ }^{140} Ce+{ }^{94} Zr+n$ is $\_ \text{MeV}$.
Given atomic masses of:
${ }^{235} U: 235.0439 \text{ u}, { }^{140} Ce: 139.9054 \text{ u},$
${ }^{94} Zr: 93.9063 \text{ u}, n: 1.0086 \text{ u},$
Value of $c^2 = 931 \text{ MeV/u}$.

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