The enolate ion that reacts with 3-buten-2-on | vedclass

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(D) The reaction shown is a Robinson annulation,which involves a Michael addition followed by an intramolecular aldol condensation. To form the produc

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(D) The reaction shown is a Robinson annulation,which involves a Michael addition followed by an intramolecular aldol condensation. To form the product $(Y)$,the enolate ion must be derived from $2-$methylcyclohexane$-1,3-$dione. The enolate ion formed at the $C-2$ position (between the two carbonyl groups) is the most stable due to resonance stabilization by both carbonyl groups. This enolate attacks the $3-$buten$-2-$one via Michael addition,followed by an intramolecular aldol condensation to yield the bicyclic product $(Y)$.

The enolate ion that reacts with $3-$buten$-2-$one to form $(Y)$ is

Similar Questions

The product $(A)$ of the following reaction is:

Consider the following reaction,where:
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