The equation of a stationary wave is y = 20 s | vedclass

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(C) The given equation of the stationary wave is $y = 20 \sin(\pi x) \cos(\omega t)$.Comparing this with the standard equation $y = A \sin(kx) \cos(\o

Vedclass · Accepted Answer

$50$

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(C) The given equation of the stationary wave is $y = 20 \sin(\pi x) \cos(\omega t)$.Comparing this with the standard equation $y = A \sin(kx) \cos(\omega t)$,we get the wave number $k = \pi 	ext{ rad/m}$.We know that $k = \frac{2\pi}{\lambda}$,so $\frac{2\pi}{\lambda} = \pi$,which gives the wavelength $\lambda = 2 	ext{ m} = 200 	ext{ cm}$.The distance between a node and its adjacent antinode is given by $\frac{\lambda}{4}$.Therefore,the distance $= \frac{200 	ext{ cm}}{4} = 50 	ext{ cm}$.

The equation of a stationary wave is $y = 20 \sin(\pi x) \cos(\omega t)$,where $x$ and $y$ are in meters and $t$ is in seconds. The distance between a node and its adjacent antinode is (in $\text{ cm}$)

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