The equation of a straight line,perpendicular to $3x - 4y = 6$ and forming a triangle of area $6$ sq. units with the coordinate axes,is

  • A
    $x - 2y = 6$
  • B
    $4x + 3y = 12$
  • C
    $4x + 3y + 24 = 0$
  • D
    $3x + 4y = 12$

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