The equation of a wave on a string of linear mass density $0.02 \text{ kg m}^{-1}$ is $Y = 0.01 \sin [2\pi (t/0.02 - x/0.50)] \text{ m}$. The tension in the string is (in $\text{ N}$)

$A$ uniform metal wire of length $L$,mass $M$,and density $\rho$ is under a tension $T$. If the speed of a transverse wave along the wire is $V$,then the area of cross-section of the wire is:

$A$ wire stretched between two rigid supports vibrates in its fundamental mode with a frequency of $50 \, Hz$. The mass of the wire is $30 \, g$ and its linear density is $4 \times 10^{-2} \, kg/m$. The speed of the transverse wave on the string is ...... $m/s$.

$A$ string of length $1 \,m$ and mass $490 \,g$ is put under a tension of $25 \,N$. $A$ wave of frequency $120 \,Hz$ is sent along it. The speed of this wave is (in $\,m/s$)

$A$ block of mass $1\, kg$ is hanging vertically from a string of length $1\, m$ and mass per unit length $\mu = 0.001\, kg/m$. $A$ small pulse is generated at its lower end. The pulse reaches the top end in approximately .... $s$.

Two strings with circular cross section and made of same material are stretched to have the same amount of tension. $A$ transverse wave is then made to pass through both the strings. The velocity of the wave in the first string having the radius of cross section $R$ is $v_1$,and that in the other string having radius of cross section $R/2$ is $v_2$. Then $\frac{v_2}{v_1} = $