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(C) Step $1$: Find the point of intersection of the lines $3x - 2y - 1 = 0$ and $x - 4y + 3 = 0$.Multiply the second equation by $3$: $3x - 12y + 9 =

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$x - y = \pi(1 - y)$

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(C) Step $1$: Find the point of intersection of the lines $3x - 2y - 1 = 0$ and $x - 4y + 3 = 0$.Multiply the second equation by $3$: $3x - 12y + 9 = 0$.Subtract this from the first equation: $(3x - 2y - 1) - (3x - 12y + 9) = 0$ $\Rightarrow 10y - 10 = 0$ $\Rightarrow y = 1$.Substitute $y = 1$ into $x - 4y + 3 = 0$: $x - 4(1) + 3 = 0$ $\Rightarrow x - 1 = 0$ $\Rightarrow x = 1$.The point of intersection is $(1, 1)$.Step $2$: Find the equation of the line passing through $(1, 1)$ and $(\pi, 0)$.The slope $m = \frac{0 - 1}{\pi - 1} = \frac{-1}{\pi - 1}$.The equation is $y - 0 = \frac{-1}{\pi - 1}(x - \pi)$.$(\pi - 1)y = -x + \pi$ $\Rightarrow x + (\pi - 1)y = \pi$ $\Rightarrow x - \pi = -(\pi - 1)y$ $\Rightarrow x - \pi = -\pi y + y$ $\Rightarrow x - y = \pi - \pi y$ $\Rightarrow x - y = \pi(1 - y)$.

The equation of the line passing through the point of intersection of the lines $3x - 2y - 1 = 0$ and $x - 4y + 3 = 0$ and the point $(\pi, 0)$ is:

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