The equation of the bisectors of the angle be | vedclass

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(B) The given equation is $3 x^2-5 x y+4 y^2=0$. Comparing this with the general form $a x^2+2 h x y+b y^2=0$,we get $a=3$,$2 h=-5$,and $b=4$. The equ

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$5(x^2-y^2)=2 x y$

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(B) The given equation is $3 x^2-5 x y+4 y^2=0$. Comparing this with the general form $a x^2+2 h x y+b y^2=0$,we get $a=3$,$2 h=-5$,and $b=4$. The equation of the bisectors of the angle between the pair of lines is given by $\frac{x^2-y^2}{a-b} = \frac{x y}{h}$. Substituting the values,we get $\frac{x^2-y^2}{3-4} = \frac{x y}{-5/2}$. This simplifies to $\frac{x^2-y^2}{-1} = \frac{2 x y}{-5}$. Multiplying both sides by $-5$,we get $5(x^2-y^2) = 2 x y$.

The equation of the bisectors of the angle between the lines represented by $3 x^2-5 x y+4 y^2=0$ is

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