The equation of the line passing through the points $(3, 4, -7)$ and $(6, -1, 1)$ is
- A$\frac{x-3}{3} = \frac{y-4}{-5} = \frac{z+7}{8}$
- B$\frac{x-3}{3} = \frac{y-4}{5} = \frac{z+7}{8}$
- C$\frac{x-3}{-3} = \frac{y-4}{-5} = \frac{z+7}{8}$
- D$\frac{x-3}{3} = \frac{y-4}{-5} = \frac{z-7}{8}$
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