The equation of the line passing through the points $(3, 2, 4)$ and $(4, 5, 2)$ is
- A$\frac{x + 3}{1} = \frac{y + 2}{3} = \frac{z + 4}{-2}$
- B$\frac{x - 3}{1} = \frac{y - 2}{3} = \frac{z - 4}{-2}$
- C$\frac{x + 3}{7} = \frac{y + 2}{7} = \frac{z + 4}{6}$
- D$\frac{x - 3}{7} = \frac{y - 2}{7} = \frac{z - 4}{6}$
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