The equation of the lines passing through the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given slopes are $m_1 = 3$ and $m_2 = -\frac{1}{3}$.Since the lines pass through the origin,their equations are $y = 3x$ and $y = -\frac{1}{3}x$.R

Vedclass · Accepted Answer

$3x^2 + 8xy - 3y^2 = 0$

Vedclass · Answer

(B) Given slopes are $m_1 = 3$ and $m_2 = -\frac{1}{3}$.Since the lines pass through the origin,their equations are $y = 3x$ and $y = -\frac{1}{3}x$.Rearranging these,we get $(y - 3x) = 0$ and $(3y + x) = 0$.The combined equation of the pair of lines is $(y - 3x)(3y + x) = 0$.Expanding this,we get $3y^2 + xy - 9xy - 3x^2 = 0$,which simplifies to $3y^2 - 8xy - 3x^2 = 0$,or $3x^2 + 8xy - 3y^2 = 0$.

The equation of the lines passing through the origin and having slopes $3$ and $-\frac{1}{3}$ is

Similar Questions

If $f(x) = \frac{\cos^2 x + \sin^4 x}{\sin^2 x + \cos^4 x}$, for $x \in R$, then $f(2002)$ is equal to

The amplitude of a damped oscillator decreases to $0.9$ times its original magnitude in $5\,s$. In another $10\,s$ it will decrease to $\alpha$ times its original magnitude,where $\alpha$ equals

Which of the following substances will not give a borax bead test?

In which of the following ionization processes does the bond energy increase and the magnetic behaviour change from paramagnetic to diamagnetic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module