The equation of the pair of lines joining the | vedclass

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(D) Given the circle $x^2+y^2=9$ and the line $x+y=3$. To find the equation of the pair of lines joining the origin to the points of intersection,we h

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$xy = 0$

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(D) Given the circle $x^2+y^2=9$ and the line $x+y=3$. To find the equation of the pair of lines joining the origin to the points of intersection,we homogenize the equation of the circle using the equation of the line. Since $x+y=3$,we have $\frac{x+y}{3}=1$. Substituting this into the circle equation: $x^2+y^2=9(1)^2$ $x^2+y^2=9\left(\frac{x+y}{3}\right)^2$ $x^2+y^2=9\left(\frac{x^2+y^2+2xy}{9}\right)$ $x^2+y^2=x^2+y^2+2xy$ $2xy=0$ $xy=0$ Thus,the equation of the pair of lines is $xy=0$.

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$(b)$ Trichoderma polysporum	$(ii)$ Butyric acid
$(c)$ Monascus purpureus	$(iii)$ Citric acid
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The equation of the pair of lines joining the origin to the points of intersection of $x^2+y^2=9$ and $x+y=3$ is:

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