The equivalent conductances of two strong electrolytes at infinite dilution in $H_2O$ (where ions move freely through a solution) at $25 ^\circ C$ are given below:
$\Lambda _{CH_3COONa}^o = 91.0 \ S \ cm^2 / equiv.$
$\Lambda _{HCl}^o = 426.2 \ S \ cm^2 / equiv.$
What additional information/quantity one needs to calculate $\Lambda ^o$ of an aqueous solution of acetic acid?

  • A
    $\Lambda ^o$ of chloroacetic acid $(ClCH_2COOH)$
  • B
    $\Lambda ^o$ of $NaCl$
  • C
    $\Lambda ^o$ of $CH_3COOK$
  • D
    The limiting equivalent conductance of $H^{+} ( \lambda _{H^{+}}^o )$

Explore More

Similar Questions

An increase in molar conductance of a strong electrolyte with dilution is mainly due to

The specific conductance of a $0.01 \, M \, KCl$ solution at $25 \, ^{\circ}C$ is $0.0014 \, \Omega^{-1} \, cm^{-1}$. Its equivalent conductance is ..... (in $\Omega^{-1} \, cm^{2} \, eq^{-1}$).

Define $\Lambda _m = \frac{\kappa \times 1000}{C}$ where $C$ is concentration in $mol \ L^{-1}$ and $\kappa$ is conductivity in $S \ cm^{-1}$.

For a strong electrolyte,the molar conductivity is given by $\wedge _m = \wedge _m^o - 10 \sqrt{C}$. Calculate $\wedge _m$ at $0.01 \ M$ if its value at $0.16 \ M$ is $200 \ S \ cm^2 \ mol^{-1}$.

The molar conductivity of $0.1 \ M$ $BaCl_2$ solution is $106 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ at $25^{\circ} C$. What is its conductivity?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo