The equivalent weight of $KMnO_4$ in alkaline medium will be

In the reaction,$MnO_{4(aq)}^{-} + Br_{(aq)}^{-} \rightarrow MnO_{2(s)} + BrO_{3(aq)}^{-}$,the correct change in oxidation number of the species involved is

The oxidation states of sulphur in $S_8$,$S_2F_2$,and $H_2S$ respectively,are:

The oxidation number of $N$ in $NH_4Cl$ is

Give the rules for the calculation of oxidation number.

Define the oxidation states of $Mn$ in the products of the given reaction:
$3K_2MnO_4 + 2H_2O + 4CO_2 \rightarrow 2KMnO_4 + MnO_2 + 4KHCO_3$