The expression for the solubility product of $Al_2(SO_4)_3$ is

  • A
    $K_{sp} = [Al^{3+}] [SO_4^{2-}]$
  • B
    $K_{sp} = [Al^{3+}]^2 [SO_4^{2-}]^3$
  • C
    $K_{sp} = [Al^{3+}]^3 [SO_4^{2-}]^2$
  • D
    $K_{sp} = [Al^{3+}]^2 [SO_4^{2-}]^2$

Explore More

Similar Questions

$A$ solution is $0.1 \ M$ in $Cl^{-}$ and $0.001 \ M$ in $CrO_{4}^{2-}$. Solid $AgNO_{3}$ is gradually added to it. Assuming that the addition does not change in volume and $K_{sp}(AgCl) = 1.7 \times 10^{-10} \ M^{2}$ and $K_{sp}(Ag_{2}CrO_{4}) = 1.9 \times 10^{-12} \ M^{3}$. Select the correct statement from the following:

Given that the solubility product constants $(K_{sp})$ follow the order $K_{sp}(Mg(OH)_2) > K_{sp}(Zn(OH)_2) > K_{sp}(Fe(OH)_3)$,what is the order of precipitation of these hydroxides?

Difficult
View Solution

If the solubility product of $PbS$ is $3.4 \times 10^{-28}$,what is the minimum concentration of sulfide ions required to precipitate $PbS$ from a $0.001 \ M \ Pb^{2+}$ solution?

The solubility of calcium carbonate $(CaCO_3)$ at $298 \ K$ is $6.4 \times 10^{-5} \ mol \ dm^{-3}$. Calculate the value of solubility product $(K_{sp})$ at the same temperature.

The solubility of $AgCl$ in its solution is $1.25 \times 10^{-5} \ mol \ dm^{-3}$. What is the solubility product of $AgCl$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo