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(A) At the moment the switch $K$ is turned $ON$ $(t = 0)$, the current through the inductors cannot change instantaneously. Therefore, the inductors a

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(A) At the moment the switch $K$ is turned $ON$ $(t = 0)$, the current through the inductors cannot change instantaneously. Therefore, the inductors act as open circuits (infinite resistance).In the given circuit, the branch containing the first inductor and the branch containing the second inductor will have zero current.Only the middle branch, which contains a single resistor of $9 \ \Omega$, will conduct current.The equivalent resistance of the circuit at $t = 0$ is $R_{eq} = 9 \ \Omega$.The voltage of the battery is $V = 9 \ V$.Using Ohm's law, the current $I$ through the ammeter is:$I = \frac{V}{R_{eq}} = \frac{9 \ V}{9 \ \Omega} = 1 \ A$.

The figure shows a circuit containing three resistors ($9 \ \Omega$ each) and two inductors ($4 \ mH$ each). The reading of the ammeter at the moment the switch $K$ is turned $ON$ is $...... \ A$.

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