The final product (IV) obtained in the reacti | vedclass

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(D) The reaction sequence is as follows:$1$. Toluene is oxidized by $KMnO_4/OH^-$ followed by $H^+$ to form benzoic acid $(I = C_6H_5COOH)$.$2$. Benzo

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$C_6H_5NH_2$

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(D) The reaction sequence is as follows:$1$. Toluene is oxidized by $KMnO_4/OH^-$ followed by $H^+$ to form benzoic acid $(I = C_6H_5COOH)$.$2$. Benzoic acid reacts with $SOCl_2$ to form benzoyl chloride $(II = C_6H_5COCl)$.$3$. Benzoyl chloride reacts with $NH_3$ to form benzamide $(III = C_6H_5CONH_2)$.$4$. Benzamide undergoes the Hofmann bromamide degradation reaction with $OBr^-$ (formed from $Br_2/NaOH$) to yield aniline $(IV = C_6H_5NH_2)$.Thus,the final product $(IV)$ is aniline $(C_6H_5NH_2)$.

The final product $(IV)$ obtained in the reaction sequence
Toluene $\xrightarrow[{2. \ H^{+}}]{{1. \ KMnO_4/OH^{-}}} I$ $\xrightarrow{{SOCl_2}} II$ $\xrightarrow{{NH_3}} III$ $\xrightarrow{{OBr^{-}}} IV$ is

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The final product $(IV)$ obtained in the reaction sequenceToluene $\xrightarrow[{2. \ H^{+}}]{{1. \ KMnO_4/OH^{-}}} I$ $\xrightarrow{{SOCl_2}} II$ $\xrightarrow{{NH_3}} III$ $\xrightarrow{{OBr^{-}}} IV$ is