The final product A,formed in the following r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Step $1$: Hydroboration-oxidation of styrene $(Ph-CH=CH_2)$ gives anti-Markovnikov addition of water,resulting in $Ph-CH_2-CH_2-OH$.Step $2$: Reac

Vedclass · Accepted Answer

$Ph-CH_2-CH_2-CH_2-OH$

Vedclass · Answer

(D) Step $1$: Hydroboration-oxidation of styrene $(Ph-CH=CH_2)$ gives anti-Markovnikov addition of water,resulting in $Ph-CH_2-CH_2-OH$.Step $2$: Reaction with $HBr$ converts the alcohol to an alkyl bromide: $Ph-CH_2-CH_2-OH + HBr ightarrow Ph-CH_2-CH_2-Br + H_2O$.Step $3$: Formation of Grignard reagent and reaction with formaldehyde $(HCHO)$ followed by hydrolysis:$Ph-CH_2-CH_2-Br + Mg \xrightarrow{	ext{ether}} Ph-CH_2-CH_2-MgBr$$Ph-CH_2-CH_2-MgBr + HCHO ightarrow Ph-CH_2-CH_2-CH_2-OMgBr$$Ph-CH_2-CH_2-CH_2-OMgBr \xrightarrow{H_3O^{+}} Ph-CH_2-CH_2-CH_2-OH$.Thus,the final product $A$ is $Ph-CH_2-CH_2-CH_2-OH$.

The final product $A$,formed in the following reaction sequence is:
$Ph-CH=CH_2$ $\xrightarrow[\text{(iii) } HBr, \text{ (iv) } Mg, \text{ ether, then } HCHO / H_3O^{+}]{\text{(i) } BH_3, \text{ (ii) } H_2O_2, OH^{-}} A$

Similar Questions

Which of the following compounds will give butanone on oxidation with alkaline $KMnO_4$ solution?

Which of the following compounds will not give the iodoform test?

Which of the following is the correct order of boiling points for $(1^o)$ primary,$(2^o)$ secondary,and $(3^o)$ tertiary alcohols?

What are $X$ and $Y$ in the following reactions?

Which of the following sequence of reagents converts propene to $1$-chloropropane?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The final product $A$,formed in the following reaction sequence is:$Ph-CH=CH_2$ $\xrightarrow[\text{(iii) } HBr, \text{ (iv) } Mg, \text{ ether, then } HCHO / H_3O^{+}]{\text{(i) } BH_3, \text{ (ii) } H_2O_2, OH^{-}} A$