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(C) The reaction proceeds in two steps: $1$. Cyclohexylmethanamine reacts with benzoyl chloride $(C_6H_5COCl)$ in the presence of a base $(NaOH)$ to f

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(C) The reaction proceeds in two steps: $1$. Cyclohexylmethanamine reacts with benzoyl chloride $(C_6H_5COCl)$ in the presence of a base $(NaOH)$ to form an amide, $N$-(cyclohexylmethyl)benzamide, which is product $[A]$. $2$. The amide $[A]$ is then reduced using lithium aluminium hydride $(LiAlH_4)$ followed by hydrolysis $(H_2O)$ to yield the corresponding amine, $N$-benzylcyclohexylmethanamine, which is the final product $[B]$.

The final product $[B]$ is :

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