The first member of the alkyne homologous ser | vedclass

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Question

(A) The general formula for the alkyne homologous series is $C_nH_{2n-2}$,where $n$ is the number of carbon atoms.For the first member,we set $n = 2$

Vedclass · Accepted Answer

Ethyne

Vedclass · Answer

(A) The general formula for the alkyne homologous series is $C_nH_{2n-2}$,where $n$ is the number of carbon atoms.For the first member,we set $n = 2$ because a triple bond requires at least two carbon atoms.Substituting $n = 2$ into the formula: $C_2H_{2(2)-2} = C_2H_2$.$C_2H_2$ is known as ethyne (also called acetylene).Therefore,the first member of the alkyne series is ethyne.

The first member of the alkyne homologous series is:

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