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(B) Arranging the data in ascending order of magnitude,we obtain:      Height (in $cm$)    $150$    $152$    $154$    $155$    $156$    $160$    $161$

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$155$

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(B) Arranging the data in ascending order of magnitude,we obtain:      Height (in $cm$)    $150$    $152$    $154$    $155$    $156$    $160$    $161$        Number of students    $8$    $4$    $3$    $7$    $3$    $12$    $4$        Cumulative frequency    $8$    $12$    $15$    $22$    $25$    $37$    $41$  Here,the total number of items $N = 41$,which is an odd number.Hence,the median is the $\left(\frac{N + 1}{2}\right)^{th}$ item.Median = $\left(\frac{41 + 1}{2}\right)^{th} = 21^{st}$ item.From the cumulative frequency table,we find that the $21^{st}$ item corresponds to a height of $155$ $cm$ (since all items from $16^{th}$ to $22^{nd}$ are equal to $155$).Therefore,the median is $155$ $cm$.

$x_i$	$5$	$15$	$25$	$35$	$45$	$55$
$f_i$	$12$	$18$	$27$	$20$	$17$	$6$

The following data gives the distribution of height of students. The median of the distribution is:

Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$

No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$

Similar Questions

If the mean of the numbers $27 + x$,$31 + x$,$89 + x$,$107 + x$,and $156 + x$ is $82$,then the mean of $130 + x$,$126 + x$,$68 + x$,$50 + x$,and $1 + x$ is:

For a distribution $x_1, x_2, \dots, x_{101}$ such that $x_1 < x_2 < x_3 < \dots < x_{100} < x_{101}$,the mean deviation of this distribution about a number $k$ is minimum. Then $k$ is equal to which of the following?

Find the mean of the following frequency distribution:

$x_i$ $5$ $15$ $25$ $35$ $45$ $55$

$f_i$ $12$ $18$ $27$ $20$ $17$ $6$

Find the weighted mean of the first $n$ natural numbers,where the weights are equal to their squares.

Let $x_1, x_2, \ldots, x_{11}$ be $11$ distinct positive integers. If we replace the largest of these integers by the median of the other $10$ integers,then:

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Height (in $cm$)	$160$	$150$	$152$	$161$	$156$	$154$	$155$
No of students	$12$	$8$	$4$	$4$	$3$	$3$	$7$

The following data gives the distribution of height of students. The median of the distribution is: Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$ No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$