The following reaction gives:

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(B) The reaction is a Cross Cannizzaro reaction between $3,4-$dimethoxybenzaldehyde and formaldehyde $(HCHO)$ in the presence of concentrated $NaOH$.I

Vedclass · Accepted Answer

$3,4-$Dimethoxybenzyl alcohol + Formate ion

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(B) The reaction is a Cross Cannizzaro reaction between $3,4-$dimethoxybenzaldehyde and formaldehyde $(HCHO)$ in the presence of concentrated $NaOH$.In a Cross Cannizzaro reaction,the more reactive aldehyde (formaldehyde) is oxidized to the corresponding acid salt (formate,$HCOO^-$),and the less reactive aldehyde ($3$,$4$-dimethoxybenzaldehyde) is reduced to the corresponding alcohol ($3$,$4$-dimethoxybenzyl alcohol).Therefore,the products are $3,4-$dimethoxybenzyl alcohol and the formate ion $(HCOO^-)$.

Similar Questions

The given reaction is: $C_6H_5-CHO + C_6H_5-CHO \xrightarrow{Na_2[Fe(CO)_4]} C_6H_5-COOCH_2-C_6H_5$

Which of the following would undergo aldol condensation?

The product $(A)$ of the following reaction is:

Aldol condensation involving $CH_3-CHO + CH_3-CHO$ gives the product:

The major product formed in the following reaction sequence is $CH_3-CH=CH_2$ $\xrightarrow[\substack{(iii) \ CH_3-CH_2-CHO \\ (iv) \ CrO_3}]{\substack{(i) \ HBr, \text{ peroxide} \\ (ii) \ Mg}}$

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