The force required to separate two glass plat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The force $F$ required to separate two plates of area $A$ separated by a liquid film of thickness $t$ and surface tension $T$ is given by the form

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(A) The force $F$ required to separate two plates of area $A$ separated by a liquid film of thickness $t$ and surface tension $T$ is given by the formula:$F = \frac{2TA}{t}$Given:Area $A = 10^{-2} \, m^2$Thickness $t = 0.05 \, mm = 0.05 	imes 10^{-3} \, m$Surface tension $T = 70 	imes 10^{-3} \, N/m$Substituting the values:$F = \frac{2 	imes (70 	imes 10^{-3}) 	imes 10^{-2}}{0.05 	imes 10^{-3}}$$F = \frac{140 	imes 10^{-5}}{0.05 	imes 10^{-3}}$$F = \frac{140}{0.05} 	imes 10^{-2} = 2800 	imes 10^{-2} = 28 \, N$Therefore,the correct option is $A$.

The force required to separate two glass plates of area $10^{-2} \, m^2$ with a film of water $0.05 \, mm$ thick between them is ...... $N$. (Surface tension of water is $70 \times 10^{-3} \, N/m$)

Similar Questions

Let $R_1, R_2$ and $R_3$ be the radii of three mercury drops. $A$ big mercury drop is formed from them under isothermal conditions. The radius of the resultant drop is

Two small drops of mercury each of radius $r$ coalesce to form a single large drop of radius $R$. The ratio of the total surface energies before and after the change is

In Jager's method,at the time of bursting of the bubble,

The excess pressure inside one soap bubble is four times that of another. What is the ratio of the volume of the first bubble to the second bubble?

Two bubbles $A$ and $B$ $(r_A > r_B)$ are joined through a narrow tube. Then

Vedclass Test Series

Exam Paper Generator

Online Exam Module