The formation of molecular complex BF_3-NH_3 | vedclass

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(B) In $BF_3$,the boron atom is $sp^2$ hybridized and possesses an empty $p_z$ orbital. When $BF_3$ reacts with $NH_3$,the lone pair of electrons from

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from $sp^2$ to $sp^3$

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(B) In $BF_3$,the boron atom is $sp^2$ hybridized and possesses an empty $p_z$ orbital. When $BF_3$ reacts with $NH_3$,the lone pair of electrons from the nitrogen atom in $NH_3$ is donated into the empty $p_z$ orbital of boron. This coordinate covalent bond formation changes the geometry of boron from trigonal planar to tetrahedral. Consequently,the hybridization of boron changes from $sp^2$ to $sp^3$.

The formation of molecular complex $BF_3-NH_3$ results in a change in hybridization of boron

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