Which C atom is the most electronegative in t | vedclass

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(A) The structure is $CH_3^{III} - CH_2^{II} - C \equiv CH^I$.Electronegativity is directly proportional to the $s$-character of the hybrid orbital.$I

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$I$

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(A) The structure is $CH_3^{III} - CH_2^{II} - C \equiv CH^I$.Electronegativity is directly proportional to the $s$-character of the hybrid orbital.$I$: The terminal carbon is $sp$ hybridized,which has $50\% \ s$-character.$II$: The carbon in $CH_2$ is $sp^3$ hybridized,which has $25\% \ s$-character.$III$: The carbon in $CH_3$ is $sp^3$ hybridized,which has $25\% \ s$-character.Since $sp$ hybridization has the highest $s$-character,the carbon atom labeled $I$ is the most electronegative.

Which $C$ atom is the most electronegative in the structure $CH_3^{III} - CH_2^{II} - C \equiv CH^I$?

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