The formula for induced $e.m.f.$ in a coil due to change in magnetic flux through the coil is (here $A$ = area of the coil,$B$ = magnetic field).

$A$ coil has $1,000$ turns and $500 \, cm^2$ as its area. The plane of the coil is placed at right angles to a magnetic induction field of $2 \times 10^{-5} \, Wb/m^2$. The coil is rotated through $180^o$ in $0.2 \, s$. The average $e.m.f.$ induced in the coil,in milli-volts,is

In a closed circuit, there is only a coil of inductance $L$ and resistance $100 \Omega$. The coil is situated in a uniform magnetic field. Suddenly, the magnetic flux linked with the circuit changes by $5 \text{ Wb}$. What amount of charge will flow in the circuit as a result?

Faraday's laws are a consequence of the conservation of

$A$ flexible wire loop in the shape of a circle has a radius that grows linearly with time. There is a magnetic field perpendicular to the plane of the loop that has a magnitude inversely proportional to the distance from the center of the loop,i.e.,$B(r) \propto \frac{1}{r}$. How does the emf $E$ vary with time?

$A$ coil having $n$ turns and resistance $R \ \Omega$ is connected with a galvanometer of resistance $4 R \ \Omega$. This combination is moved in time $t$ seconds from a magnetic flux $\phi_1$ Weber to $\phi_2$ Weber. The induced current in the circuit is