The formula of potassium dicyanobis(oxalato)n | vedclass

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Question

(A) To determine the formula,we analyze the components of the name:$1$. The central metal is nickel $(Ni)$ with an oxidation state of $+II$.$2$. The l

Vedclass · Accepted Answer

$K_4[Ni(CN)_2(C_2O_4)_2]$

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(A) To determine the formula,we analyze the components of the name:$1$. The central metal is nickel $(Ni)$ with an oxidation state of $+II$.$2$. The ligands are two cyano groups $(CN^-)$ and two oxalato groups $(C_2O_4^{2-})$.$3$. The coordination sphere charge is calculated as: $x = (+2) + 2(-1) + 2(-2) = 2 - 2 - 4 = -4$.$4$. To balance the charge of $-4$,we need four potassium ions $(K^+)$.$5$. Thus,the formula is $K_4[Ni(CN)_2(C_2O_4)_2]$.

The formula of potassium dicyanobis(oxalato)nickelate$(II)$ is

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