The formula to find the mode of a grouped data is $\ldots \ldots \ldots . . .$
- A$Z=l+\frac{(\frac{n}{2}-cf)}{f} \times c$
- B$Z=l+\left(\frac{f_{1}-f_{0}}{2 f_{1}-f_{0}-f_{2}}\right) \times h$
- C$Z=3M - 2\bar{x}$
- D$Z= A +\frac{\sum f_{i} u_{i}}{\sum f_{i}} \times h$
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Similar Questions
Consider the following frequency distribution of the heights of $60$ students of a class:
Height (in $cm$) Number of students $150-155$ $15$ $155-160$ $13$ $160-165$ $10$ $165-170$ $8$ $170-175$ $9$ $175-180$ $5$
The sum of the lower limit of the modal class and upper limit of the median class is:
| Height (in $cm$) | Number of students |
| $150-155$ | $15$ |
| $155-160$ | $13$ |
| $160-165$ | $10$ |
| $165-170$ | $8$ |
| $170-175$ | $9$ |
| $175-180$ | $5$ |
The sum of the lower limit of the modal class and upper limit of the median class is:
Easy
View SolutionIf the mean of $12, 13, x, 17, 18$ and $20$ is $16,$ then $x = \ldots \ldots \ldots \ldots .$
Medium
View SolutionThe median class of the following frequency distribution is ...........
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $6$ $10$ $5$ $6$ $4$ $2$ $2$
| Class | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $6$ | $10$ | $5$ | $6$ | $4$ | $2$ | $2$ |
Easy
View SolutionIn the formula $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{\Sigma f_{i}}$,$d_{i} =$ .........
Easy
View SolutionTo draw the 'less than' type Ogive,........... is represented on the $X$-axis.
Easy
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