The forward biased diode connection is:

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(D) For a $p-n$ junction diode to be in forward bias,the $p$-side must be connected to a higher potential than the $n$-side.Let $V_p$ be the potential

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(D) For a $p-n$ junction diode to be in forward bias,the $p$-side must be connected to a higher potential than the $n$-side.Let $V_p$ be the potential at the $p$-side and $V_n$ be the potential at the $n$-side.Forward bias condition: $V_p > V_n$.Evaluating the options:$(A)$ $V_p = -3 \ V, V_n = +3 \ V \implies V_p $(B)$ $V_p = 2 \ V, V_n = 4 \ V \implies V_p $(C)$ $V_p = -2 \ V, V_n = +2 \ V \implies V_p $(D)$ $V_p = +2 \ V, V_n = -2 \ V \implies V_p > V_n$ (Forward bias)Therefore,option $(D)$ is the correct connection for a forward biased diode.

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