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(C) According to Einstein's photoelectric equation,the maximum kinetic energy is given by $K.E_{\max} = h
u - W$,where $h
u$ is the energy of the in

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more than two times its initial value.

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(C) According to Einstein's photoelectric equation,the maximum kinetic energy is given by $K.E_{\max} = h
u - W$,where $h
u$ is the energy of the incident photon and $W$ is the work function of the material.Initially,$K_1 = h
u - W$.When the frequency is doubled,the new frequency becomes $2
u$. The new maximum kinetic energy $K_2$ is:$K_2 = h(2
u) - W = 2h
u - W$.We can rewrite this as:$K_2 = 2(h
u - W) + W = 2K_1 + W$.Since the work function $W$ is a positive constant,$K_2 > 2K_1$.Therefore,the kinetic energy of the emitted photoelectrons will be more than two times its initial value.

The frequency of incident light falling on a photosensitive material is doubled. The kinetic energy $(K.E.)$ of the emitted photoelectrons will be:

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