When light is incident on a surface,photoelec | vedclass

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Question

(C) The kinetic energy $(KE)$ of a photoelectron is given by Einstein's photoelectric equation: $KE = h
u - W = \frac{hc}{\lambda} - W$.Here,$h$ is P

Vedclass · Accepted Answer

The value of kinetic energy is equal to or less than a maximum kinetic energy.

Vedclass · Answer

(C) The kinetic energy $(KE)$ of a photoelectron is given by Einstein's photoelectric equation: $KE = h
u - W = \frac{hc}{\lambda} - W$.Here,$h$ is Planck's constant,$
u$ is the frequency,$\lambda$ is the wavelength of incident light,and $W$ is the work function of the metal.Photoelectrons are emitted from different depths within the metal. As they travel to the surface,they undergo multiple collisions with other electrons and atoms,losing some energy. Therefore,the kinetic energy of emitted photoelectrons varies from $0$ to a maximum value $(KE_{max} = h
u - W)$.Thus,the kinetic energy of any emitted photoelectron is always equal to or less than the maximum kinetic energy.

When light is incident on a surface,photoelectrons are emitted. For these photoelectrons:

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