The function sin^2(omega t) represents | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) We know that $\sin^2(\omega t) = \frac{1 - \cos(2\omega t)}{2} = \frac{1}{2} - \frac{1}{2}\cos(2\omega t)$.This expression represents a simple har

Vedclass · Accepted Answer

a simple harmonic motion with a period $\pi /\omega$

Vedclass · Answer

(D) We know that $\sin^2(\omega t) = \frac{1 - \cos(2\omega t)}{2} = \frac{1}{2} - \frac{1}{2}\cos(2\omega t)$.This expression represents a simple harmonic motion $(SHM)$ because it is of the form $y = A + B\cos(\omega' t)$,where $A$ and $B$ are constants.The angular frequency of this motion is $\omega' = 2\omega$.The time period $T$ is given by $T = \frac{2\pi}{\omega'} = \frac{2\pi}{2\omega} = \frac{\pi}{\omega}$.Therefore,the function represents a simple harmonic motion with a period $\pi /\omega$.

The function $\sin^2(\omega t)$ represents

Similar Questions

If the angle $\theta$ between the vectors $\overrightarrow{a}=2 x^2 \hat{i}+4 x \hat{j}+\hat{k}$ and $\overrightarrow{b}=7 \hat{i}-2 \hat{j}+x \hat{k}$ is such that $90^{\circ} < \theta < 180^{\circ}$, then $x$ lies in the interval

The value of $x$,where $x>0$ and $\tan \left(\sec ^{-1}\left(\frac{1}{x}\right)\right)=\sin \left(\tan ^{-1} 2\right)$ is

$A$ coin is dropped in a lift. It takes time $t_1$ to reach the floor when the lift is stationary. It takes time $t_2$ when the lift is moving down with constant acceleration $a$. Then:

Which of the following has the lowest heat of hydrogenation per mole?

The major product of the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module