The fundamental frequency of a sonometer wire of length $l$ is $n_0$. $A$ bridge is now introduced at a distance of $\Delta l$ (where $\Delta l \ll l$) from the center of the wire. The lengths of wire on the two sides of the bridge are now vibrated in their fundamental modes. Then,the beat frequency is nearly

  • A
    $n_0 \Delta l / l$
  • B
    $8 n_0 \Delta l / l$
  • C
    $2 n_0 \Delta l / l$
  • D
    $n_0 \Delta l / 2l$

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