The fundamental frequency of vibration of a string stretched between two rigid supports is $50\,Hz$. The mass of the string is $18\,g$ and its linear mass density is $20\,g/m$. The speed of the transverse waves produced in the string is $..........\,m/s$.

$A$ uniform metal wire has length $L$,mass $M$,and cross-sectional area $A$. It is under tension $T$,and $V$ is the speed of a transverse wave along the wire. The density of the wire is:

$A$ $43\, m$ long rope of mass $5.0\, kg$ joins two rock climbers. One climber strikes the rope and the second one feels the effect $1.4\, s$ later. What is the tension in the rope in $N$?

$A$ mass of $20\ kg$ is hanging with the support of two strings of the same linear mass density. Now,pulses are generated in both strings at the same time near the joint at the mass. The ratio of the time taken by a pulse to travel through string $1$ to that taken by a pulse on string $2$ is:

$A$ pulse is generated at the lower end of a hanging rope of uniform density and length $L$. The speed of the pulse when it reaches the midpoint of the rope is:

$A$ string is producing transverse vibration whose equation is $y = 0.021 \sin(x + 30t)$,where $x$ and $y$ are in meters and $t$ is in seconds. If the linear density of the string is $1.3 \times 10^{-4} \ kg/m$,then the tension in the string in $N$ will be: