The geometry of the molecule with sp^3d^2 hyb | vedclass

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(C) The hybridization of a central atom is determined by the number of electron pairs (bonding pairs + lone pairs) around it.For $sp^3d^2$ hybridizati

Vedclass · Accepted Answer

Octahedral

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(C) The hybridization of a central atom is determined by the number of electron pairs (bonding pairs + lone pairs) around it.For $sp^3d^2$ hybridization,the number of hybrid orbitals is $1 + 3 + 2 = 6$.According to the Valence Shell Electron Pair Repulsion $(VSEPR)$ theory,a molecule with $6$ electron pairs arranged around a central atom adopts an octahedral geometry to minimize inter-electronic repulsions.Therefore,the geometry of the molecule with $sp^3d^2$ hybridized central atom is octahedral.

The geometry of the molecule with $sp^3d^2$ hybridised central atom is

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