The given potentiometer has its wire of resistance $10\, \Omega$. When the sliding contact is in the middle of the potentiometer wire,the potential drop across the $2\, \Omega$ resistor is -

  • A
    $\frac{40}{11}\, \text{V}$
  • B
    $10\, \text{V}$
  • C
    $\frac{40}{9}\, \text{V}$
  • D
    $5\, \text{V}$

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