The greatest value of the function -5 sin the | vedclass

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Question

(B) The expression is of the form $a \sin 	heta + b \cos 	heta$.The maximum value of this expression is given by the formula $\sqrt{a^2 + b^2}$.Here

Vedclass · Accepted Answer

$13$

Vedclass · Answer

(B) The expression is of the form $a \sin 	heta + b \cos 	heta$.The maximum value of this expression is given by the formula $\sqrt{a^2 + b^2}$.Here,$a = -5$ and $b = 12$.Substituting these values into the formula:Maximum value $= \sqrt{(-5)^2 + (12)^2}$$= \sqrt{25 + 144}$$= \sqrt{169}$$= 13$.Therefore,the greatest value is $13$.

The greatest value of the function $-5 \sin \theta + 12 \cos \theta$ is

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