The hardness of a water sample containing 10^ | vedclass

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Question

(D) Hardness in terms of $CaCO_{3}$ equivalents is calculated by converting the concentration of the salt to the equivalent concentration of $CaCO_{3}

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(D) Hardness in terms of $CaCO_{3}$ equivalents is calculated by converting the concentration of the salt to the equivalent concentration of $CaCO_{3}$.Given concentration of $MgSO_{4} = 10^{-3} \; M = 10^{-3} \; mol/L$.Since $1 \; mol$ of $MgSO_{4}$ is equivalent to $1 \; mol$ of $CaCO_{3}$ (both have a valency factor of $2$),the concentration of $CaCO_{3}$ equivalents is $10^{-3} \; mol/L$.Mass of $CaCO_{3} = 10^{-3} \; mol 	imes 100 \; g/mol = 0.1 \; g$ in $1 \; L$ of water.$ppm$ is defined as parts per million,which is $mg$ of solute per $L$ of solution.$0.1 \; g = 100 \; mg$.Therefore,the hardness is $100 \; ppm$.

The hardness of a water sample containing $10^{-3} \; M \; MgSO_{4}$ expressed as $CaCO_{3}$ equivalents (in $ppm$) is (molar mass of $MgSO_{4}$ is $120.37 \; g/mol$)

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