The heat of combustion of methane is -800 kJ | vedclass

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(C) The molar mass of methane $(CH_{4})$ is $16 \ g \ mol^{-1} = 16 	imes 10^{-3} \ kg \ mol^{-1}$.Given that the heat of combustion for $1 \ mol$ $(

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$-20 \ kJ$

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(C) The molar mass of methane $(CH_{4})$ is $16 \ g \ mol^{-1} = 16 	imes 10^{-3} \ kg \ mol^{-1}$.Given that the heat of combustion for $1 \ mol$ $(16 	imes 10^{-3} \ kg)$ of $CH_{4}$ is $-800 \ kJ$.To find the heat of combustion for $4 	imes 10^{-4} \ kg$ of $CH_{4}$,we use the unitary method:$\Delta H = \frac{-800 \ kJ}{16 	imes 10^{-3} \ kg} 	imes (4 	imes 10^{-4} \ kg)$$\Delta H = -800 	imes \frac{4 	imes 10^{-4}}{16 	imes 10^{-3}}$$\Delta H = -800 	imes \frac{4}{16} 	imes 10^{-1}$$\Delta H = -800 	imes 0.25 	imes 0.1 = -20 \ kJ$.

The heat of combustion of methane is $-800 \ kJ \ mol^{-1}$. What is the heat of combustion for $4 \times 10^{-4} \ kg$ of methane?

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