The height of the water level in a tank of uniform cross-section is $5 \,m$. The volume of water leaked in $5 \,s$ through a hole of area $2.4 \,mm^2$ made at the bottom of the tank is (Assume the level of the water in the tank remains constant and acceleration due to gravity $= 10 \,ms^{-2}$).

  • A
    $90 \times 10^{-6} \,m^3$
  • B
    $120 \times 10^{-6} \,m^3$
  • C
    $80 \times 10^{-6} \,m^3$
  • D
    $40 \times 10^{-6} \,m^3$

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