The higher number of unpaired electrons are i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The atomic number of $Fe$ is $26$. The electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$. Number of unpaired electrons in $Fe$: $3d^6$ has $4$

Vedclass · Accepted Answer

$Fe^{3+}$

Vedclass · Answer

(D) The atomic number of $Fe$ is $26$. The electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$. Number of unpaired electrons in $Fe$: $3d^6$ has $4$ unpaired electrons. Electronic configuration of $Fe^+$ is $[Ar] 3d^6 4s^1$. Number of unpaired electrons in $Fe^+$: $3d^6$ $(4)$ + $4s^1$ $(1)$ = $5$ unpaired electrons. Electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$. Number of unpaired electrons in $Fe^{2+}$: $3d^6$ has $4$ unpaired electrons. Electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$. Number of unpaired electrons in $Fe^{3+}$: $3d^5$ has $5$ unpaired electrons. Both $Fe^+$ and $Fe^{3+}$ have $5$ unpaired electrons,but in standard chemistry problems of this type,$Fe^{3+}$ is the most stable ion with $5$ unpaired electrons. However,based on the options provided,$Fe^{3+}$ is the standard answer for the highest number of unpaired electrons in common oxidation states.

List-$I$ (Property)	List-$II$ (Metal)
$A$. Element with maximum second ionization enthalpy	$i$. $Co$
$B$. Element with maximum third ionization enthalpy	$ii$. $Cr$
$C$. $M$ in $M(CO)_6$	$iii$. $Cu$
$D$. Element with maximum enthalpy of atomization	$iv$. $Zn$
	$v$. $Ni$

The higher number of unpaired electrons are in

Similar Questions

The lanthanide contraction is responsible for the fact that

What is the total number of transition series of $d$-block elements?

The calculated spin-only magnetic moment of $Cr^{2+}$ ion is: (in $text{ BM}$)

Which of the following elements does not exhibit variable valency?

Vedclass Test Series

Exam Paper Generator

Online Exam Module