The huge amount of energy which is released during atomic fission is due to

  • A
    Loss of mass
  • B
    Loss of electrons
  • C
    Loss of protons
  • D
    Loss of $\alpha$-particles

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Similar Questions

The atomic mass of an element is $12.00710 \, amu$. If there are $6$ neutrons in the nucleus of the atom of the element,the binding energy per nucleon of the nucleus will be $....... \, MeV$.
($e^{-} = 0.00055 \, amu$,$p = 1.00814 \, amu$,$n = 1.00893 \, amu$)

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Let $m_p$ be the mass of a proton,$m_n$ that of a neutron,$M_1$ that of a $_{10}^{20}Ne$ nucleus,and $M_2$ that of a $_{20}^{40}Ca$ nucleus. Then:

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