The hybridization states of the central atom | vedclass

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(D) $1$. In $[Fe(CN)_6]^{3-}$,$Fe$ is in $+3$ oxidation state $(3d^5)$. $CN^-$ is a strong field ligand,causing pairing of electrons,resulting in $d^2

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all $d^2sp^3$

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(D) $1$. In $[Fe(CN)_6]^{3-}$,$Fe$ is in $+3$ oxidation state $(3d^5)$. $CN^-$ is a strong field ligand,causing pairing of electrons,resulting in $d^2sp^3$ hybridization.$2$. In $[Fe(CN)_6]^{4-}$,$Fe$ is in $+2$ oxidation state $(3d^6)$. $CN^-$ is a strong field ligand,causing pairing of electrons,resulting in $d^2sp^3$ hybridization.$3$. In $[Co(NO_2)_6]^{3-}$,$Co$ is in $+3$ oxidation state $(3d^6)$. $NO_2^-$ is a strong field ligand,causing pairing of electrons,resulting in $d^2sp^3$ hybridization.$4$. Therefore,all three complexes exhibit $d^2sp^3$ hybridization.

Hybridisation	Geometry	Complex structure
$(A) \ sp^3$	$(i) \ \text{Square planar}$	$(p) \ [Fe(CN)_6]^{3-}$
$(B) \ d^2sp^3$	$(ii) \ \text{Tetrahedral}$	$(q) \ [ZnCl_4]^{2-}$
$(C) \ dsp^2$	$(iii) \ \text{Octahedral}$	$(r) \ [Ni(NH_3)_4]^{2+}$
-	$(iv) \ \text{Linear}$	$(s) \ [Ag(CN)_2]^-$

The hybridization states of the central atom in the complexes $[Fe(CN)_6]^{3-}$,$[Fe(CN)_6]^{4-}$ and $[Co(NO_2)_6]^{3-}$ are

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